Our Solar System

Lesson plan · University · Ages 18 and over · 45 minutes

Eclipse geometry and the Saros

Why an eclipse needs syzygy and a node, how eclipse seasons and the eclipse year follow from the Moon's regressing nodes, and why eclipses repeat after a Saros of 223 lunations, shown with real eclipses from 2009 to 2029.

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Level
Ages
18 and over
To present
45 minutes
Steps presented
7
Steps for pupils
8
Questions
7
Pupil tasks
1

The lesson

The class works out why eclipses need a new or full Moon close to a node, estimates the eclipse limit from the sizes and distances of the Sun and Moon, and follows one eclipse season of 2029 in the viewer. They derive the eclipse year from the regression of the nodes, show why 223 lunations make a Saros, and compare two total eclipses of Saros 136, 22 July 2009 and 2 August 2027.

What they take away

An eclipse needs syzygy with the Moon within about 17 degrees of a node, so eclipses come in seasons 173.3 days apart, half an eclipse year of 346.62 days. 223 synodic, 242 draconic and 239 anomalistic months all come to about 6,585.3 days, so one Saros later the geometry repeats a third of a turn of the Earth further west.

Step by step

The caption is what the class reads on screen; the talking points are in your notes drawer (N) when you present. Steps marked Pupils only appear only in the pupil lesson.

  1. 01

    Syzygy at a node

    Presented and for pupils

    Caption

    The total lunar eclipse of 26 June 2029, at true scale. Sun, Earth and Moon are in a line at full Moon, and the Moon is at a node, where its tilted orbit crosses the ecliptic.

    Talking points

    • USNO glossary: syzygy is a configuration where three or more bodies are approximately in a straight line, and also the times of new and full Moon. A node is either point where the plane of an orbit crosses a reference plane.
    • NASA eclipse site: the Moon's orbit is inclined at a mean 5.145 degrees to Earth's. At the ascending node the Moon crosses the ecliptic from south to north, at the descending node from north to south.
    • NASA: greatest eclipse at 03:23:22 TD, umbral magnitude 1.844. The Saros 130 catalogue gives gamma 0.0124 (NASA's key: the distance from the axis of Earth's shadow to the Moon's centre, in Earth equatorial radii), so the Moon passes almost through the middle of the shadow, and 1 hour 41 minutes 53 seconds of totality, the longest of its series. Lunar Saros 130 eclipses happen at the Moon's ascending node.
    • The viewer works out the umbral magnitude from its own geometry and gets 1.834. The clock runs at five minutes a second.

    Sources 2 4 9 13 16Present from this step

  2. 02

    How close to a node?

    Presented and for pupils

    Caption

    Two weeks earlier, at new Moon on 12 June 2029, the Moon was farther from the node: its shadow's axis missed Earth and only the penumbra touched the Arctic, a partial eclipse.

    Talking points

    • NASA: 12 June 2029, partial, magnitude 0.458, Saros 118, seen from the Arctic, Scandinavia, Alaska, northern Asia and northern Canada. The Saros 118 catalogue gives gamma 1.2943: NASA's key defines gamma as the distance of the shadow cone's axis from Earth's centre in equatorial radii, so here the axis passes above the North Pole. The viewer's geometry gives 1.2964.
    • NASA: if new Moon takes place within about 17 degrees of a node, a solar eclipse will be visible from somewhere on Earth. The actual value ranges from 15.39 to 18.59 degrees with the eccentricity of the Moon's and Earth's orbits.
    • An estimate of that limit: seen from Earth's centre, some observer on Earth sees the discs touch if the Moon's ecliptic latitude β is less than the Moon's horizontal parallax minus the Sun's plus both semi-diameters. With NASA's mean distances and radii (Moon 384,400 km and 1,737.4 km, Sun 149.598 million km and 695,700 km, Earth's equatorial radius 6,378.1 km) those are 0.951, 0.002, 0.259 and 0.266 degrees, so β < 1.474 degrees. At a distance u from the node the Moon's latitude is given by sin β = sin i · sin u, so u < arcsin(sin 1.474° / sin 5.145°) = 16.7 degrees.
    • The estimate treats the Moon as fixed at conjunction; NASA's figure comes from the full calculation.

    Ask the class

    The Moon's horizontal parallax is 0.951°, the Sun's 0.002°, and their semi-diameters 0.259° and 0.266°. The Moon's orbit is inclined 5.145°. Within how many degrees of a node must new Moon fall for a solar eclipse? Give one decimal place.

    Answer16.7 degrees. Answers from 16.2 to 17.2 are marked right.

    Whyβ_max = 0.951 − 0.002 + 0.259 + 0.266 = 1.474°. sin u = sin β_max / sin i = 0.02572/0.08968 = 0.2868, so u = 16.7°. NASA gives about 17°, from 15.39° to 18.59° as the distances change.

    Sources 1 3 5 11 18 19 20Present from this step

  3. 03

    Half a lunation later

    Pupils only

    Caption

    Your turn. The clock starts at the total lunar eclipse of 26 June 2029, a full Moon at a node. Run it to the next new Moon and pause, then decide what happens there.

    Talking points

    • USNO: full Moon on 26 June 2029 at 03:22 UT and new Moon on 11 July 2029 at 15:51 UT. The viewer finds the new Moon two minutes later.
    • The check passes within 3 degrees of new Moon, about six hours either side.
    • The view is side-on to the ecliptic at true scale, so the Moon's height above or below the ecliptic shows the tilt of its orbit.

    Pupil question

    What happens at the new Moon you found, on 11 July 2029?

    1. A partial solar eclipse, seen from southern Chile and ArgentinaRight answer
    2. A total solar eclipse across the tropics
    3. Nothing: half a lunation is too long for the Sun to still be near a node

    WhyNASA lists a partial solar eclipse on 11 July 2029, magnitude 0.230, seen from southern Chile and Argentina. In the half lunation since the lunar eclipse the Sun has moved about 15 degrees along the ecliptic, still inside the roughly 17 degree limit round the node, so the new Moon still eclipses part of the Sun.

    Pupil task

    Run the clock forward from the lunar eclipse. Pause it at the next new Moon, when the Moon is between Earth and the Sun.

    HintNew Moon is about two weeks after full Moon. Slow the clock down as the Moon swings round towards the Sun.

    The viewer checks the task as the pupil works and says when it is done.

    Sources 8 11 17Open this step as a pupil

  4. 04

    One season, three eclipses

    Presented and for pupils

    Caption

    The partial eclipse of 11 July 2029: the third of three in one eclipse season, after the partial solar eclipse of 12 June and the total lunar eclipse of 26 June.

    Talking points

    • NASA: the Sun moves along the ecliptic at 0.99 degrees a day and takes 34.5 days to cross the 34 degree wide eclipse zone round each node. The synodic month is 29.53 days, so every eclipse season has one solar eclipse and possibly two. The mid-points of eclipse seasons are 173.3 days apart.
    • NASA: 11 July 2029, partial, magnitude 0.230, Saros 156. The Saros 156 catalogue gives gamma −1.4191: the axis passes below the South Pole. That series began with a partial eclipse on 1 July 2011, so this is its second eclipse.
    • NASA (Periodicity of Solar Eclipses, table 5): two solar eclipses one lunation apart have Saros numbers that differ by 38, and 118 + 38 = 156.
    • Both solar eclipses of this season are at the Moon's descending node (Saros 118 and 156 catalogues), the lunar eclipse between them at the ascending node (lunar Saros 130): at full Moon the Moon is on the far side of Earth from the Sun, at the opposite node. NASA's lunar catalogue marks it "pp": the solar eclipses before and after it are both partial.
    • Intervals from NASA's TD times: 13.97 days from the June solar eclipse to the lunar one, 15.51 days from that to the July solar eclipse, 29.48 days between the two solar eclipses.

    Ask the class

    Why can one eclipse season hold two solar eclipses?

    1. The Sun takes about 34.5 days to cross the eclipse zone round a node, longer than one 29.53-day lunationRight answer
    2. The Moon's orbit lies flat in the ecliptic during an eclipse season
    3. There are two new Moons in every calendar month in summer

    WhyNASA: the eclipse zone is 34 degrees wide and the Sun takes 34.5 days to cross it, so two new Moons 29.53 days apart can both fall inside. The orbit stays tilted: over 2008 to 2010 NASA finds its inclination between 5.00 and 5.30 degrees, always near the largest at eclipses.

    Sources 1 4 5 8 9 11 13Present from this step

  5. 05

    The eclipse year

    Presented and for pupils

    Caption

    The nodes slide west round the ecliptic once every 18.6 years, so the Sun meets the same node again after 346.62 days, an eclipse year. This annular eclipse of 6 February 2027 is one season before the total eclipse of 2 August.

    Talking points

    • NASA: the lunar nodes rotate westward along the ecliptic at 0.05295 degrees a day; one complete rotation takes 18.6 years (6,793.48 days) with respect to the fixed stars. USNO glossary: the eclipse year, between successive passages of the Sun through the same node, is approximately 346.62 days.
    • Derivation: against the stars the Sun moves east at 360/365.25636 degrees a day (JPL's sidereal year) and the node west at 360/6,793.48, so they meet again after 1/(1/365.25636 + 1/6,793.48) = 346.62 days. Half of that, 173.31, is NASA's 173.3 days between the mid-points of eclipse seasons.
    • The same reasoning gives the draconic month, node to node: 1/(1/27.32166 + 1/6,793.48) = 27.2122 days, NASA's 27.21222.
    • NASA: 6 February 2027 is annular (Saros 131, magnitude 0.928, 7 minutes 51 seconds at greatest eclipse) and 2 August 2027 total (Saros 136). They are 176.75 days apart, close to six lunations (177.18 days), and NASA's table 5 says six lunations on adds 5 to the Saros number: 131 + 5 = 136.
    • NASA's Saros 131 catalogue: the annular eclipse of 26 January 2009 (07:59:45 TD, lunation 112) is one Saros before this one (16:00:48 TD, lunation 335), 6,585.33 days and 223 lunations earlier.

    Ask the class

    The sidereal year is 365.25636 days and the Moon's nodes go once round against the stars, westward, in 6,793.48 days. How long is the eclipse year in days? Give two decimal places.

    Answer346.62 days. Answers from 346.52 to 346.72 are marked right.

    WhyThe Sun and the node move towards each other, so their rates add: 1/365.25636 + 1/6,793.48 = 0.00273780 + 0.00014720 = 0.00288500 per day, and 1/0.00288500 = 346.62 days, the USNO value. Subtracting the rates, as if the node moved east, would give 386.0 days.

    Sources 1 2 6 11 16 21Present from this step

  6. 06

    Three months in step

    Presented and for pupils

    Caption

    223 synodic, 242 draconic and 239 anomalistic months all come to about 6,585.3 days. After one Saros the Moon is new again, near the same node and at nearly the same distance.

    Talking points

    • NASA (Periodicity of Solar Eclipses): synodic month 29.530589 days, anomalistic month (perigee to perigee) 27.554550 days, draconic month (node to node) 27.212221 days, their values for 2000.
    • NASA: 242 draconic months are 6,585.3575 days and 239 anomalistic months 6,585.5375 days. 223 × 29.530589 = 6,585.3213 days; NASA prints 6,585.3223 next to a day count of 6,585 d 07 h 43 m, which matches 6,585.3213. That is about 18 years 11 days 8 hours.
    • NASA: two eclipses one Saros apart happen at the same node, with the Moon at nearly the same distance from Earth and at the same time of year. 19 eclipse years, 6,585.78 days, are about 11 hours longer than the Saros, so the Sun is back near the same node too.
    • The scene opens at the greatest eclipse of 2 August 2027, side-on to the ecliptic at true scale. Saros 136 eclipses are at the descending node (NASA's catalogue).

    Ask the class

    By how many minutes do 242 draconic months (27.212221 days each) exceed 223 synodic months (29.530589 days each)?

    Answer52 minutes. Answers from 50 to 54 are marked right.

    Why242 × 27.212221 = 6,585.3575 days and 223 × 29.530589 = 6,585.3213 days. The difference is 0.0362 days, 52 minutes, which NASA gives as the mean difference between the two cycles in the Saros. In that time the Moon moves 0.0362 × 360/27.212221 = 0.48 degrees relative to its node, NASA's shift of the node with each eclipse in a series.

    Sources 1 7 16Present from this step

  7. 07

    One Saros earlier: 22 July 2009

    Presented and for pupils

    Caption

    The total solar eclipse of 22 July 2009, also Saros 136, one Saros before 2027. Its shadow crossed India and China and reached the central Pacific, with up to 6 minutes 39.5 seconds of totality.

    Talking points

    • NASA: 22 July 2009, total, greatest eclipse 02:36:25 TD, Saros 136, magnitude 1.080, 6 minutes 39 seconds at greatest eclipse; totality over India, Nepal, China and the central Pacific.
    • NASA's path table: greatest eclipse at 02:35:18.1 UT, 24° 13.3' N, 144° 07.1' E, with ΔT = 65.9 s, and the longest totality, 6 minutes 39.5 seconds, at 02:29:16 UT. The scene opens at greatest eclipse.
    • NASA's Saros 136 catalogue numbers this eclipse's lunation 118 and the 2027 eclipse's 341 (lunations counted from 6 January 2000): 223 apart. Gamma grows from 0.0698 to 0.1421 between them, as the Moon moves north with each eclipse of the series.
    • The viewer's calendar runs from 2026, so this eclipse cannot open in eclipse mode. The shadow here comes from the same geometry, whose axis meets the ground at 24.18° N, 143.89° E at this moment, about 0.2 degrees from NASA's point, with gamma 0.0701.

    Ask the class

    NASA gives greatest eclipse on 22 July 2009 at 02:36:25 TD and on 2 August 2027 at 10:07:49 TD. How many days apart are they? Give two decimal places.

    Answer6,585.31 days. Answers from 6,585.304 to 6,585.316 are marked right.

    Why22 July 2009 to 22 July 2027 is 18 years with four 29 Februarys between (2012, 2016, 2020, 2024): 18 × 365 + 4 = 6,574 days. On to 2 August adds 11: 6,585 days. 10:07:49 − 02:36:25 = 7 h 31 min 24 s = 0.3135 days. Total 6,585.31 days, within 12 minutes of the mean Saros, 6,585.3213 days.

    Sources 3 7 10 14Present from this step

  8. 08

    A third of a turn west

    Presented and for pupils

    Caption

    18 years, 11 days and 7.5 hours later: 2 August 2027. In the extra third of a day Earth turns a third of the way round, so the eclipse falls about 111 degrees farther west, over Egypt.

    Talking points

    • NASA's path table: greatest eclipse at 10:06:37.7 UT, 25° 30.3' N, 33° 11.0' E, ΔT = 71.7 s, with 6 minutes 22.6 seconds of totality there. The viewer's calendar opens it at 10:06:40 UTC, NASA's TD time less 69 seconds.
    • NASA's Saros 136 catalogue, greatest-eclipse longitudes: 105.2° W in 1991, 144.1° E in 2009, 33.2° E in 2027, 78.5° W in 2045, each about 111 degrees farther west. NASA: the extra third of a day means Earth turns an extra 120 degrees or so each cycle, and the series returns to about the same region every three Saros (the Exeligmos, about 54 years 34 days).
    • NASA: even-numbered solar Saros series are at the descending node and their gamma increases: 0.0698, 0.1421 and 0.2116 for 2009, 2027 and 2045.
    • The lunar eclipses repeat too. The total lunar eclipse of 31 December 2028, in the viewer's calendar, is one Saros after that of 21 December 2010: both are lunar Saros 125, with umbral magnitudes 1.246 and 1.256, 6,585.36 days apart. Five 29 Februarys fall between them, so the calendar gap is 18 years 10 days.
    • The clock runs at a minute a second.

    Ask the class

    The mean Saros is 6,585.3213 days. Through how many degrees does Earth turn, relative to the Sun, in the 0.3213 day beyond the whole days?

    Answer116 degrees. Answers from 111 to 121 are marked right.

    WhyEarth turns 360 degrees a day relative to the Sun, so 0.3213 × 360 = 115.7 degrees: the next eclipse of the series falls that much farther west. NASA rounds the fraction to a third of a day, 120 degrees. From 2009 to 2027 the interval was 6,585.3135 days and the greatest-eclipse point moved 110.9 degrees west.

    Sources 1 7 12 13 15Present from this step

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Sources

Every fact in this lesson comes from these sources, and each step lists the ones it uses.

  1. Periodicity of Solar Eclipses, NASA Eclipse Web Site (Fred Espenak)
  2. Eclipses and the Moon's Orbit, NASA Eclipse Web Site (Fred Espenak)
  3. Key to Catalog of Solar Eclipse Saros Series, NASA Eclipse Web Site (Fred Espenak)
  4. Key to Catalog of Lunar Eclipse Saros Series, NASA Eclipse Web Site (Fred Espenak)
  5. Catalog of Solar Eclipses of Saros 118, NASA Eclipse Web Site (Fred Espenak)
  6. Catalog of Solar Eclipses of Saros 131, NASA Eclipse Web Site (Fred Espenak)
  7. Catalog of Solar Eclipses of Saros 136, NASA Eclipse Web Site (Fred Espenak)
  8. Catalog of Solar Eclipses of Saros 156, NASA Eclipse Web Site (Fred Espenak)
  9. Catalog of Lunar Eclipses of Saros 130, NASA Eclipse Web Site (Fred Espenak)
  10. Solar Eclipses: 2001 to 2010, NASA Eclipse Web Site (Fred Espenak)
  11. Solar Eclipses: 2021 to 2030, NASA Eclipse Web Site (Fred Espenak)
  12. Lunar Eclipses: 2001 to 2010, NASA Eclipse Web Site (Fred Espenak)
  13. Lunar Eclipses: 2021 to 2030, NASA Eclipse Web Site (Fred Espenak)
  14. Total Solar Eclipse of 2009 July 22: path of the eclipse, NASA Eclipse Web Site (Fred Espenak)
  15. Total Solar Eclipse of 2027 August 02: path of the eclipse, NASA Eclipse Web Site (Fred Espenak)
  16. Astronomical Almanac Glossary, US Naval Observatory
  17. Phases of the Moon from 20 June 2029, US Naval Observatory
  18. Moon Fact Sheet, NASA NSSDCA
  19. Earth Fact Sheet, NASA NSSDCA
  20. Sun Fact Sheet, NASA NSSDCA
  21. Astrodynamic Parameters, JPL Solar System Dynamics

More University lessons

Our Solar System · 3dsolarsystem.online/teachers/lessons/saros-cycle/

Eclipse geometry and the Saros

NameDate
  1. The Moon's horizontal parallax is 0.951°, the Sun's 0.002°, and their semi-diameters 0.259° and 0.266°. The Moon's orbit is inclined 5.145°. Within how many degrees of a node must new Moon fall for a solar eclipse? Give one decimal place.

    degrees

  2. What happens at the new Moon you found, on 11 July 2029?

    • A. A partial solar eclipse, seen from southern Chile and Argentina
    • B. A total solar eclipse across the tropics
    • C. Nothing: half a lunation is too long for the Sun to still be near a node
  3. Why can one eclipse season hold two solar eclipses?

    • A. The Sun takes about 34.5 days to cross the eclipse zone round a node, longer than one 29.53-day lunation
    • B. The Moon's orbit lies flat in the ecliptic during an eclipse season
    • C. There are two new Moons in every calendar month in summer
  4. The sidereal year is 365.25636 days and the Moon's nodes go once round against the stars, westward, in 6,793.48 days. How long is the eclipse year in days? Give two decimal places.

    days

  5. By how many minutes do 242 draconic months (27.212221 days each) exceed 223 synodic months (29.530589 days each)?

    minutes

  6. NASA gives greatest eclipse on 22 July 2009 at 02:36:25 TD and on 2 August 2027 at 10:07:49 TD. How many days apart are they? Give two decimal places.

    days

  7. The mean Saros is 6,585.3213 days. Through how many degrees does Earth turn, relative to the Sun, in the 0.3213 day beyond the whole days?

    degrees

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